Caribexams math exam guide for the CXC CSEC May/June 2010 exams is posted
Caribexams math exam guide for the CXC CSEC May/June 2010 exams is posted!
Even though I didn't have much to do with it, I am still announcing that the caribexams math exam guide for the CXC CSEC May/ June 2010 exam is now posted in the community.
This math exam guide is meant to guide students sitting the CXC CSEC math exam in May/June 2010 and forward.
The new CXC CSEC math exam marking scheme for May/June 2010 is posted, and so are the topics for paper 1 and paper 2 of the May/June 2010 math exam.
Since the new (May/June 2010 and forward) math guide is NOT for students sitting the CXC CSEC math exam in January 2010, the old caribexams CXC CSEC math guide will remain posted for their use.
So for now, caribexams will provide guides for the two math exams, January 2010 (the old guide) and May/June 2010 (the new guide).
The time management guide for the CXC CSEC math exam stays the same since the number of questions to be answered in the exam remains the same.
I hope our members and guests find this updated CXC math exam guide useful.
i need some assistance in the topic of genetics
Can some demonstrate to me how to solve:
Question: Solve the following pair of equations for x&y:
y+4x=27
xy+x=40
y+4x=27.. equation 1
xy+x=40.. equation 2
from eq 1 y=27-4x
so x[27-4x]+x=4o
27x-4x*+x=40 {*means squared}
28x-4x*=40
-4x*+28x-40=o....quadratic eq
-4x*+20x+8x-40=0
-4x[x-5] +8[x-5]=o
[-4x+8][x-5]=o
-4x+8=0 x-5=0
x=-8/-4 x=5
either x=2 or x=5
when x=2 in eq 1 when x=5 in eq 1
y+4[2]=27 y+4[5]=27
y=19 y=7
...theres probably a shorter way to do it
i really need some help in maths..............